WebApr 17, 2024 · Step 3: Apply the zero-product property and set each variable factor equal to zero. 2x + 3 = 0 or x + 5 = 0. Step 4: Solve the resulting linear equations. 2x + 3 = 0 or x + 5 = 0 2x = − 3 x = − 5 2x 2 = − 3 2 x = − 3 2. Answer: The solutions are − 5 and − 3 2. The check is optional. WebJul 25, 2015 · The equation 5x2 + 9x − 2 is of the form ax2 +bx + c = 0 where: a = 5,b = 9,c = − 2. The Discriminant is given by: Δ = b2 − 4 ⋅ a ⋅ c. = (9)2 − (4) ⋅ (5) ⋅ ( − 2) = 81 +40 = 121. As Δ > 0 there are two solutions. The solutions are found using the formula. x = …
Factor completely 5x2 - 40. 5(x + 8)(x - 8), 5(x2 - 8), 5(x + 8)(x - 5 ...
Web9. Devide:(10x^3+5x^2+75x-40)÷(2x+1) (10x³+5x²+75x-40)÷(2x+1) 10 5 75 -40 [-½]....-5 0 -75/2-----10 0 75 [-155/2] Answer: 10x²+75 Remainder : -155/2 10. factor completely 80ax³ - 75x² - 15a²x⁵ Answer: ayt. Step-by-step explanation: sori pi bob* pi aq sa math. kaya mo na siguro yan. 11. solution of (10x^3+5x^2+75x-40)by(2x-1) Answer ... Web9. Factor completely 2x3 – 28x2 + 98x.a. (x + 7)(x-7)b. 2x(x - 72C.(x - 7)2d. (x + 7)?7 10. One factor of 28x2+x-15 is 4x+3,what is the other factor? 11. divide 28x2 + 36x - 16 by 4 12. Divide 35x4 – 14x3 – 28x2 by 7x2. What is the quotient? a. 5x2 – 2x – 4 b. 5x2 – 2x – 3 c. 5x2 + 2x – 4 d. 5x2 + 2x + 4 13. new york jets schedule 2022 2023
Solve x^3-5x^2-4x+20 Microsoft Math Solver
WebAlgebra questions and answers. Section 6.3: Factoring Difference of Two Squares (DOTS) Binomial, Factor by Grouping, 6. Factor Completely; if the expression is prime then indicate so: 1) 9b2−16c2 2) 3x2−2x+5 3) 7x2+21x−x−3 4) x2−8x−9 5) 3x2−18x+4x−24 6) 5x2−10x+15 7) 4x2−40x 8) 4x2+25y2 9) 3x2−6x+24 10) x2−36 11) 2x2− ... WebTo use the direct factoring method, the equation must be in the form x^2+Bx+C=0.This is achieved by dividing both sides of the equation by 5 r + s = -4 rs = -12 Let r and s be the … WebFor factoring polynomials, "factoring" (or "factoring completely") is always done using some set of numbers as possible coefficient. We say we are factoring "over" the set. #x^3 -x^2-5x+5# can be factored. over the integers as # (x-1) (x^2-5)#. #x^2-5# cannot be factored using integer coefficients. (It is irreducible over the integers.) mililani community athletic association